Code Enforcement Salary in Florida
$21.3K - $25.8K
2% of jobs
$25.8K - $30.3K
8% of jobs
$30.3K - $34.8K
14% of jobs
$35.1K is the 25th percentile. Wages below this are outliers.
$34.8K - $39.2K
17% of jobs
The median wage is $41.9K / yr.
$39.2K - $43.7K
15% of jobs
$43.7K - $48.2K
12% of jobs
$51K is the 75th percentile. Wages above this are outliers.
$48.2K - $52.7K
12% of jobs
$52.7K - $57.2K
8% of jobs
$57.2K - $61.7K
5% of jobs
$61.7K - $66.1K
4% of jobs
$66.1K - $70.6K
3% of jobs
$21.3K
$42.6K
$70.2K
$44,811
/year
$21.54
/hour
Code Enforcement Salary Comparison by Location
Nationwide
United States
$59,965
Florida
Florida
$44,811
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How much does a Code Enforcement make in Florida?
As of Aug 20, 2026, the average annual pay for a Code Enforcement in Florida is $44,811 a year.
Just in case you need a simple salary calculator, that works out to be approximately $21.54 an hour. This is the equivalent of $861/week or $3,734/month.
While ZipRecruiter is seeing salaries as high as $70,246 and as low as $21,298, the majority of Code Enforcement salaries currently range between $35,100 (25th percentile) to $51,600 (75th percentile) with top earners (90th percentile) making $62,772 annually in Florida. The average pay range for a Code Enforcement varies greatly (by as much as 16500), which suggests there may be many opportunities for advancement and increased pay based on skill level, location and years of experience.
Florida ranks number 50 out of 50 states nationwide for Code Enforcement salaries.
To estimate the most accurate annual salary range for Code Enforcement jobs, ZipRecruiter continuously scans its database of millions of active jobs published locally throughout America.
Find your next high paying job as a Code Enforcement on ZipRecruiter today.
What are Top 10 Highest Paying Cities for Code Enforcement Jobs in Florida
We've identified 10 cities where the typical salary for a Code Enforcement job is above the average in Florida in Florida. Topping the list is Summerland Key, , with Miami Dade County, and Sanibel, close behind in the second and third positions. Sanibel, beats the average in Florida by $15,972 (35.6%), and Summerland Key, furthers that trend with another $19,056 (42.5%) above the $44,811 average.
With these 10 cities paying on average above the average for Florida, the opportunities for economic advancement by changing locations as a Code Enforcement appears to be exceedingly fruitful.
Finally, another factor to consider is the average salary for these top 10 cities varies very little at 9% between Summerland Key, and Deerfield Beach, , reinforcing the limited potential for much wage advancement. The possibility of a lower cost of living may be the best factor to use when considering location and salary for a Code Enforcement role.
City | Annual Salary | Hourly Wage |
|---|---|---|
Summerland Key | $63,867 | $30.71 |
Miami Dade County | $61,073 | $29.36 |
Sanibel | $60,783 | $29.22 |
Port Saint Lucie | $59,963 | $28.83 |
Port St Lucie | $59,963 | $28.83 |
Pace | $59,599 | $28.65 |
Lauderhill | $59,568 | $28.64 |
Plantation | $59,563 | $28.64 |
Miami Beach | $59,216 | $28.47 |
Deerfield Beach | $58,021 | $27.89 |
What are Top 0 Best Paying Related Code Enforcement Jobs in Florida
Analyzing similar jobs related to the Code Enforcement job category in Florida, we found 0 that were relevant. However, none pay more than the $44811 state average for Code Enforcement jobs.
Job Title | Annual Salary | Hourly Wage |
|---|
About Our Data
ZipRecruiter salary estimates, histograms, trends and comparisons are derived from both employer job postings and third party data sources.
